34m^2+62m-60=0

Solution for 34m^2+62m-60=0 equation:

34m^2+62m-60=0

a = 34; b = 62; c = -60;
Δ = b2-4ac
Δ = 622-4·34·(-60)
Δ = 12004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12004}=\sqrt{4*3001}=\sqrt{4}*\sqrt{3001}=2\sqrt{3001}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{3001}}{2*34}=\frac{-62-2\sqrt{3001}}{68}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{3001}}{2*34}=\frac{-62+2\sqrt{3001}}{68}
$